2x^2+17x=14-8x

Solution for 2x^2+17x=14-8x equation:

2x^2+17x=14-8x

We move all terms to the left:

2x^2+17x-(14-8x)=0

We add all the numbers together, and all the variables

2x^2+17x-(-8x+14)=0

We get rid of parentheses

2x^2+17x+8x-14=0

We add all the numbers together, and all the variables

2x^2+25x-14=0

a = 2; b = 25; c = -14;
Δ = b2-4ac
Δ = 252-4·2·(-14)
Δ = 737
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{737}}{2*2}=\frac{-25-\sqrt{737}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{737}}{2*2}=\frac{-25+\sqrt{737}}{4}
$